Ask Question
3 June, 17:12

A hockey goalie is standing on ice. Another player fires a puck (m = 0.170 kg) at the goalie with a velocity of + 41.0 m/s. (a) If the goalie catches the puck with his glove in a time of 2.33 x 10-3 s, what is the magnitude of the average force exerted on the goalie by the puck?

+4
Answers (1)
  1. 3 June, 20:59
    0
    2991.42 N

    Explanation:

    For this problem, we'll use the equations: momentum = mass x velocity and impulse = change in momentum, and impulse=force x time.

    initial momentum; p1 = 0.17 x 41 = 6.97 kg. m/s

    final momentum; p2 = 0, because final velocity is 0 m/s

    Thus,

    impulse = p1 - p2 = 6.97 - 0 = 6.97 kg. m/s

    Finally, impulse = Force x time,

    Thus, Force = Impulse/time

    Force = 6.97 / (2.33 x 10^ (-3)) = 2991.42 N
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A hockey goalie is standing on ice. Another player fires a puck (m = 0.170 kg) at the goalie with a velocity of + 41.0 m/s. (a) If the ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers