Ask Question
25 March, 16:22

The cable supporting a 2130-kg elevator has a maximum strength of 2.18*104 n. what maximum upward acceleration can it give the elevator without breaking?

+3
Answers (1)
  1. 25 March, 17:24
    0
    Answer;

    =0.43 m/s²

    Solution;

    There will be the tension in the cable, T, upwards and the weight of the elevator, mg, downwards.

    By Newton's second law, the sum of the forces will be equal to mass*acceleration.

    Resultant force = m * a

    Then T - mg = ma so the tension in the cable is

    T = m (g+a)

    The cable will break when T = 21,800 N

    Solving for a, that happens when

    a = 21800/2130 - g

    = 10.23 - g (in m/s^2)

    If you're using g = 9.8 m/s^2

    Then the maximum acceleration allowed is 10.23-9.8 = 0.43 m/s^2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The cable supporting a 2130-kg elevator has a maximum strength of 2.18*104 n. what maximum upward acceleration can it give the elevator ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers