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4 November, 04:18

A box contains about 5.64 x 1021 hydrogen

atoms at room temperature 21°C.

Find the thermal energy of these atoms.

Answer in units of J.

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Answers (1)
  1. 4 November, 06:47
    0
    Given that,

    The temperature of atom is 21°C

    θ = 21 + 273 = 294K.

    Then, from kinetic theory,

    The kinetic energy of individual elements is

    K. E = 2kT/3

    k is Boltzmann constant

    k = 1.38 * 10^-23 J/K•particle

    Then,

    K. E = 2 * 1.38 * 10^-23 * 294 / 3

    K. E = 2.7048 * 10^-21 J/particle

    Each particle of hydrogen is 5.64 * 10²¹ particle

    Total K. E = 2.7048 * 10^-21 * 5.64 * 10²¹

    Total K. E = 15.26 J
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