A hollow conducting sphere has an inner radius of r1 = 0.19 m and an outer radius of r2 = 0.34 m. The sphere has a net charge of Q = 1.8E-06 C. What is the field E1 in N/C 1 m from the sphere's outer surface?

9022.0539 v/m

Explanation:

We know as given:

r1 = 0.19

r2 = 0.34

Q = 1.8 * 10⁻⁶ C

and it is known that E1 = k * q/r² (k = 9 * 10⁹)

= 9 * 10⁹ * 1.8 * 10⁻⁶ / (1+0.34) ²

= 9022.0539 v/m

Thus, the correct answer is = E1 = 9022.0539 v/m.