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3 May, 12:07

A charge of + 3.0 mC is distributed uniformly along the circumference of a circle with a radius of 20 cm. How much external energy is required to bring a charge of 25mC from infinity to the center of the circle?

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  1. 3 May, 15:16
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    Work done = 4584.9 J

    Explanation:

    given: q1=3.0 mC = 3.0 * 10⁻³ C, r = 20 cm = 0.20 m, q1 = 34μC = 34 * 10⁻⁶ C

    Solution:

    Formula for the potential difference at the center of the circle

    P. E = K * q1 q2 / r (Coulomb's constant k = 8.99 * 10⁹ N·m² / C²)

    P. E = 8.99 * 10⁹ N·m² / C² * 3.0 * 10⁻³ C * 34 * 10⁻⁶ C / 0.20 m

    P. E = 4584.9 J = Work done
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