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16 October, 23:43

How much work must be done to stop an 1 800kg vehicle travelling at 30 m/s?

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  1. 17 October, 00:05
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    810 kJ

    Explanation:

    Work done is equal to change in kinetic energy

    W=∆KE

    Change in kinetic energy is given by

    ∆KE=½m (v²-u²)

    Where ∆KE is the change in kinetic energy, m is mass of the vehicle, v is final velocity while u is initial velocity.

    Since the vehicle must come to rest, the final velocity is zero.

    Substituting 1800 kg for m, 0 m/s for v and 30 m/s for u then

    ∆KE=½*1800 (0²-30²) = -810, 000J

    Converted into kJ

    ∆KE=-810 kJ

    Therefore, work done is 810 kJ
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