The force required to stretch a Hooke's-law

spring varies from 0 N to 62.4 N as we stretch

the spring by moving one end 17.2 cm from

its unstressed position.

Find the force constant of the spring.

Answer in units of N/m.

Find the work done in stretching the spring.

Answer in units of J.

Question

Physics

Johnathan Mason

10 March, 17:23

The force required to stretch a Hooke's-law

spring varies from 0 N to 62.4 N as we stretch

the spring by moving one end 17.2 cm from

its unstressed position.

Find the force constant of the spring.

Answer in units of N/m.

Find the work done in stretching the spring.

Answer in units of J.

+1

Answers (1)

Know the Answer?

Maci Howe · Answer 1

I think this is correct, but I am not entirely certain.

Find the force constant of the spring:

F = - KX

(0 - 62.4) = - K (0.172m)

-362.791 = - K

362.791 N/m = K

Find the work done in stretching the spring:

W = (1/2) KX

W = (1/2) (362.791) (0.172m)

W = 31.2 J

The force required to stretch a Hooke's-lawspring varies from 0 N to 62.4 N as we stretchthe spring by moving one end 17.2 cm fromits unstressed position.Find the force constant of the spring.Answer in units of N/m.Find the work done in stretching the spring.Answer in units of J.

The force required to stretch a Hooke's-law

spring varies from 0 N to 62.4 N as we stretch

the spring by moving one end 17.2 cm from

its unstressed position.

Find the force constant of the spring.

Answer in units of N/m.

Find the work done in stretching the spring.

Answer in units of J.