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10 March, 17:23

The force required to stretch a Hooke's-law

spring varies from 0 N to 62.4 N as we stretch

the spring by moving one end 17.2 cm from

its unstressed position.

Find the force constant of the spring.

Answer in units of N/m.

Find the work done in stretching the spring.

Answer in units of J.

+1
Answers (1)
  1. 10 March, 20:56
    0
    I think this is correct, but I am not entirely certain.

    Find the force constant of the spring:

    F = - KX

    (0 - 62.4) = - K (0.172m)

    -362.791 = - K

    362.791 N/m = K

    Find the work done in stretching the spring:

    W = (1/2) KX

    W = (1/2) (362.791) (0.172m)

    W = 31.2 J
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Home » Physics » The force required to stretch a Hooke's-law spring varies from 0 N to 62.4 N as we stretch the spring by moving one end 17.2 cm from its unstressed position. Find the force constant of the spring. Answer in units of N/m.
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