A model electric train requires 3.7267 V to operate. If the primary coil of its transformer has 184.463 turns windings, how many windings should the secondary have if the primary is connected to a 100.864 V household circuit? Answer in units of turns.

= 6.815 turns

Explanation:

From the Turn ratio equation;

Ns/Np = Vs/Vp

Where; Ns and Np is the number of turns in the secondary and primary coil respectively.

Vs and Vp are the voltages in the secondary and primary coils respectively.

Since; Vs = 3.7267 V, Vp = 100.864 V, Ns = ? and Np = 184.463 turns

Thus;

Ns = (Np * Vs) / Vp

= (184.463*3.7267) / 100.864

= 6.815 turns

Therefore, the number of windings in the secondary coil should be 6.815 turns.