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30 December, 18:38

A certain planet has an escape speed V. If another planet has twice size and twice the mass of the first planet, its escape speed will be

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  1. 30 December, 20:22
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    The escape speed on the other planet is V

    Explanation:

    Escape velocity V = √2GM/R where M = mass of planet and R = radius of planet. G = gravitational constant

    Let V₁ and V₂ be the escape speeds on planet one and two respectively.

    if V₁ = √2GM₁/R₁ and V₂ = √2GM₂/R₂ and M₂ = 2M₁ and R₂ = 2R₁ (since it is twice the size of the first planet)

    V₂ = √2GM₂/R₂ = V₂ = √ (2G * 2M₁/2R₁) = √2GM₁/R₁ = V₁ = V

    So the escape speed on the other planet is V
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