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4 August, 02:45

Sound travels about 750 miles per hour. if you stand in a canyon and sound a horn, you will hear an echo. suppose it takes about 1.5 seconds to hear the echo. how far away is the canyon wall, in feet? feet now let's generalize that result. suppose it takes n seconds to hear the echo. how far away is the canyon wall, in terms of n? preview feet

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  1. 4 August, 04:01
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    1. Answer;

    -825 feet (825 ft)

    Explanation;

    Let the canyon wall be at W feet

    The speed of the sound is 750 mph

    The distance will be (2 * W) (because the echo is a reflected sound)

    The time is 1.5 seconds

    Speed = distance / time

    but; 1 mile = 5280 ft and 1 hour = 3600 s

    Thus; 2W/1.5 = (750 mph) * (5280 ft/1 mile) * (1h / 3600 s)

    W = 1100 * 1.5/2

    = 825 ft

    2. Answer;

    = 550n ft

    Explanation;

    Speed = Distance/time

    The speed = 750 mph

    Time = n seconds

    Distance = 2 W

    1 mile = 5280 ft, and 1 h = 3600 secs

    Therefore; 2W/n = (750 mph) x (5280 ft / 1 mile) x (1h / 3600 s)

    = 2 W/n = 1100

    = 2 W = 1100n

    W = 550n ft

    Thus in terms of n the distance of the canyon from the wall is 550n ft
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