A child sits 6 m away from the center of the merry go round. The centripetal acceleration acting on the child' is 3.6 m/s^2. What is the tangential velocity of the child?

A 4.65 m/s

B 21.6

C 0.6 m/s

D 1.67 m/s

Question

Physics

Clare Stuart

21 October, 02:38

A child sits 6 m away from the center of the merry go round. The centripetal acceleration acting on the child' is 3.6 m/s^2. What is the tangential velocity of the child?

A 4.65 m/s

B 21.6

C 0.6 m/s

D 1.67 m/s

+1

Answers (1)

Know the Answer?

Sylvia Ryan · Answer 1

The centripetal acceleration is related to the tangential velocity according to the equation below.

a=v²/r where v is the tangential velocity and r the radius of the circular path.

thus v²=a*r

From the question provided, r=6m acceleration = 3.6m/s²

Therefore using these values in the formula v²=a*r

v=√ (3.6*6)

v=√21.6

v=4.65

The answer is A. 4.65 m/s

A child sits 6 m away from the center of the merry go round. The centripetal acceleration acting on the child' is 3.6 m/s^2. What is the tangential velocity of the child?A 4.65 m/sB 21.6C 0.6 m/sD 1.67 m/s

A child sits 6 m away from the center of the merry go round. The centripetal acceleration acting on the child' is 3.6 m/s^2. What is the tangential velocity of the child?

A 4.65 m/s

B 21.6

C 0.6 m/s

D 1.67 m/s