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21 April, 16:16

A force of 1.5 * 102 N is exerted on a charge of 1.4 * 10-7 C that is traveling at an angle of 75° to a magnetic field.

If the charge is moving at 1.3 * 106 m/s, what is the magnetic field strength?

8.2 * 102 T

8.5 * 102 T

3.2 * 103 T

6.4 * 1010 T

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Answers (2)
  1. 21 April, 17:13
    0
    Answer: B
  2. 21 April, 18:43
    0
    Option (B) is correct. The magnetic field strength=8.5 x 10² T

    Explanation:

    the magnetic force Fm is given by

    Fm = q V B sinθ

    q = charge=1.4 x 10⁻⁷ C

    v = velocity = 1.3 x 10⁶ m/s

    B = magnetic field strength

    Fm = magnetic force = 1.5 x 10² N

    θ=75°

    so 1.5 x 10² = (1.4 x 10⁻⁷) (1.3 x 10⁶) (B) sin75

    B=8.5 x 10² T
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