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28 August, 15:12

A 13,000 kg helicopter accelerates upward a 0.5 m/s^2 while lifting a 2000 pound car. to the nearest newton, what is the lift force exerted by the air on the rotors? use 4.45 n = 1 lb.

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  1. 28 August, 15:18
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    Lift force exerted by the air on the rotors=143244 N

    Explanation:

    we use Newtons second law

    F - (M+m) g = (M+m) a

    F = lift force

    m = mass of helicopter = 13000 Kg

    M = mass of car = 2000 lb=907.2 kg

    a = acceleration = 0.5 m/s²

    g = acceleration due to gravity

    F - (M+m) g = (M+m) a

    F = (M+m) (a+g)

    F = (13000+907.2) (0.5+9.8)

    F=143244 N
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