A 13,000 kg helicopter accelerates upward a 0.5 m/s^2 while lifting a 2000 pound car. to the nearest newton, what is the lift force exerted by the air on the rotors? use 4.45 n = 1 lb.

Question

Physics

Jair Cowan

6 October, 00:36

A 13,000 kg helicopter accelerates upward a 0.5 m/s^2 while lifting a 2000 pound car. to the nearest newton, what is the lift force exerted by the air on the rotors? use 4.45 n = 1 lb.

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Answers (1)

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Rhys Deleon · Answer 1

Lift force exerted by the air on the rotors=143244 N

Explanation:

we use Newtons second law

F - (M+m) g = (M+m) a

F = lift force

m = mass of helicopter = 13000 Kg

M = mass of car = 2000 lb=907.2 kg

a = acceleration = 0.5 m/s²

g = acceleration due to gravity

F - (M+m) g = (M+m) a

F = (M+m) (a+g)

F = (13000+907.2) (0.5+9.8)

F=143244 N