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10 June, 03:46

n the calibration step of a thermochemistry experiment, a current of 124/text{ mA}124 mA, from a 24.0/text{ V}24.0 V source was allowed to flow through the electrical heater for 219/text{ s}219 s and was found to result in an increase in the temperature of the calorimeter and its contents of + 1.39/text{ K}+1.39 K. Given that the energy supplied by an electrical circuit is the voltage multiplied by the current, multiplied by the time, what is the heat capacity of the calorimeter and its contents?

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  1. 10 June, 04:39
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    Answer: C = 468.88 J/kgk

    Explanation: Given that the

    Current I = 124 mA

    Voltage V = 24 V

    Time t = 219 s

    Change in temperature Ø = 1.39 K

    Heat energy = mcØ

    Also,

    Heat energy = IVt

    Where c = specific heat capacity

    IVt = mcØ

    Let assume that the mass is negligible or a unit mass = 1kg

    124 * 10^-3 * 24 * 219 = 1.39c

    C = 651.744/1.39

    C = 468.88 J/kgk
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