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16 September, 20:36

Marcia flew her ultralight plane to a nearby town against a head wind of 15 km/h in 2h 20 min. the return trip under the same wind conditions took 1h 24min. find the plane's air speed and the distance to the nearby town

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Answers (2)
  1. 16 September, 20:42
    0
    The answer to this question would be 60km per hour
  2. 17 September, 00:17
    0
    Let the distance between the towns be d and the speed of the air be s.

    distance = speed * time

    convert the minutes time into hours.

    When flying into the wind, ground speed will be air speed MINUS wind speed, hence the against the wind trip is described by:

    d

    s-15

    =

    7

    3

    return trip is then:

    d

    s+15

    =

    7

    5

    Cross-multiplying both we get the two-variable system:

    3d=7∗ (s-15) 5d=7∗ (s+15)

    3d=7s-1055d=7s+105

    subtract first equation from second equation we get

    2d=210d=105km

    Substitute the value of d in the above equations for s.

    5∗105=7s+1057s=420s=60km/hr
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