You are designing a new solenoid and experimenting with material for each turn. The particular turn you are working with is a circular loop of radius 3.00 cm that carries a current of 12.0 A. Calculate the magnetic field B at the center of the loop.

The magnitude of the magnetic field B at the center of the loop is 5.0272 x 10⁻⁴ T.

Explanation:

Given;

Radius of circular loop, R = 3.00 cm = 0.03 m

Current in the loop, I = 12.0 A

Magnetic field at the center of circular loop is given as;

B = μ₀I / 2R

Where;

μ₀ is constant = 4π x 10⁻⁷ T. m/A

R is the radius of the circular loop

I is the current in the loop

Substitute the given values in the above equation and calculate the magnitude of the magnetic field;

B = (4π x 10⁻⁷ x 12) / 0.03

B = 5.0272 x 10⁻⁴ T

Therefore, the magnitude of the magnetic field B at the center of the loop is 5.0272 x 10⁻⁴ T.