A man walks backward on a bus. To a stationary observer, the bus moves

east at a speed of 15 m/s. If the man moves 2.3 m/s west relative to the bus,

what is his velocity in the frame of reference of a stationary observer?

V (m, b) = V (m, e) - V (b, e)

2.3m/s (west) = V (m, e) - 15m/s (east)

to solve this change the direction of slower speed. so it will become negative value

-2.3m/s (east) = V (m, e) - 15m/s (east)

V (m, e) = 15m/s (east) - 2.3m/s (east)

V (m, e) = 12.7 m/s (east)

velocity of the man in frame of reference of stationary observer is 12.7 m/s

it's slightly less than the velocity of bus so stationary observer see the man move slower than the one inside the bus

ps: - V (m, b) - velocity of man relative to bus

V (b, e) - velocity of bus relative to earth

V (m, e) - velocity of man relative to earth