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26 June, 02:24

A uniform magnetic field of magnitude 0.23 T is directed perpendicular to the plane of a rectangular loop having dimensions 7.8 cm by 14 cm. Find the magnetic flux through the loop.

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  1. 26 June, 04:34
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    Ф = 2.51mWb

    Explanation:

    Given Area 7.8cm by 14cm = 109.2cm² = 109.2*10-⁴m²

    B = 0.23T.

    Ф = BACosθ

    Ф = magnetic flux through the area.

    B = magnetic field strength

    A = Area of the loop through which there is a magnetic flux.

    θ = angle between the normal to the area and the direction of the magnetic field. The normal is a perpendicular line directed out of the plane of the loop. It is a vector for the area.

    Assuming that the normal to the area is perpendicular to the magnetic field vector, that is θ = 0°,

    Ф = 0.23 * 109.2*10-⁴ Cos0° = 2.51*10-³Wb = 2.51mWb.
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