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25 January, 02:29

An unknown material, m1 = 0.45 kg, at a temperature of T1 = 91 degrees C is added to a Dewer (an insulated container) which contains m2 = 1.3 kg of water at T2 = 23 degrees C. Water has a specific heat of cw = 4186 J / (kg⋅K). After the system comes to equilibrium the final temperature is T = 31.4 degrees C.

a. Input an expression for the specific heat of the unknown material.

b. What is the specific heat in J (kgK) ?

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  1. 25 January, 04:20
    0
    Let the specific heat of material be s

    heat lost by material = m₁ s (T 1 - T), (T 1 - T) is fall in temp, m₁ is mass of material

    =.45 x s x (91 - 31.4)

    = 26.82 s

    Heat gained by water

    = m₂ cw (T2 - T)

    1.3 x 4186 x (31.4 - 23)

    heat lost = heat gained

    m₂ cw (T2 - T) = m₁ s (T 1 - T)

    1.3 x 4186 x (31.4 - 23) =.45 x s x (91 - 31.4)

    45711.12 = 26.82 s

    s = 1704.36
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