Ask Question
24 February, 00:13

A girl on a bike is moving at a speed of 1.40 m/s at the start of a 2.15 m high and 12.4 m long incline. The total mass is 57.0 kg, air resistance and rolling resistance can be modeled as a constant friction force of 41.0 N, and the speed at the lower end of the incline is 6.80 m/s. Determine the work done (in J) by the girl as the bike travels down the incline.

+2
Answers (1)
  1. 24 February, 01:14
    0
    568.16J

    Explanation:

    V = 1.4 m/s

    h = 2.15m

    H = 12.4m

    M = 57.0kg

    Fr = 41.0N

    Vb = 6.80m/s

    g = 9.8m/s²

    K. E at the top + P. E at the top + Work done = K. E at the bottom + frictional force.

    ½mv² + mgh + W = ½mVb + Fr. H

    (½ * 57 * 1.4²) + (57 * 9.8 * 2.15) + W = (½ * 57 * 6.8²) + (41 * 12.4)

    55.86 + 1202.22 + w = 1317.84 + 508.4

    1258.08 + w = 1828.24

    W = 1826.24 - 1258.08

    W = 568.16J
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A girl on a bike is moving at a speed of 1.40 m/s at the start of a 2.15 m high and 12.4 m long incline. The total mass is 57.0 kg, air ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers