A 80 mW laser beam is polarized horizontally. It then passes through two polarizers. The axis of the first polarizer is oriented at 30∘ from the horizontal, and that of the second is oriented at 60∘ from the horizontal.

The E (incident) for the first polarizer is E (incident) = -76.1930384332

The E (incident) for the second polarizer is E (incident) = 12.340115991

Explanation:

Solving the problem:

Given

Transmitted data = 80 mW

First polarizer = 30 degree

Second polarizer = 60 degree

We have the formula,

E (transmitted) = E (incident) cos ()

1. Through the first polarizer

E (transmitted) = E (incident) cos ()

80=E (incident) cos (60 degree) (according to law subtract the given degree with 90 degree).

Then,

E (incident) = E (transmitted) cos ()

E (incident) = 80*cos 60 degree

E (incident) = -76.1930384332

The E (incident) for the first polarizer is E (incident) = -76.1930384332

2. Through the first polarizer

We have the formula,

E (transmitted) = E (incident) cos ()

80=E (incident) cos (30 degree) (according to law subtract the given degree with 90 degree).

Then,

E (incident) = E (transmitted) cos ()

E (incident) = 80*cos 30 degree

E (incident) = 12.340115991

The E (incident) for the second polarizer is E (incident) = 12.340115991