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10 November, 12:17

A diver of mass 101 kg jumps upward off a diving board into water. Diving board is 6m above water. Diver has a speed of 1.2m/s. based on speed how high above the board will the diver reach?

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  1. 10 November, 13:11
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    When the diver reaches maximum height, the upward velocity will be zero.

    We shall use the formula

    v^2 = u^2 - 2gh

    where

    v = 0 (velocity at maximum height)

    u = 1.2 m/s, intial upward velocity

    g = - 9.8 m/s^2, gravitational acceleration (downward)

    h = maximum height attained above the diving board.

    Therefore

    0 = 1.2^2 - 2*9.8*h

    h = 1.2^2 / (2*9.8) = 0.0735 m

    Answer: 0.074 m (nearest thousandth)
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