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17 September, 20:36

A playground merry-go-round has a radius of 3.0 m and a rotational inertia of 600 kg. m2. it is initially spinning at 0.80 rad/s when a 20-kg child crawls from the center to the rim. when the child reaches the rim the angular velocity of the merry-go-round is:

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  1. 17 September, 23:15
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    The solution for this problem is:

    Compute first for the initial Inertia:

    Initial inertia = 600 + (20 * (0 ^ 2)) = 600 kg m^2 since the radius of the child is 0 originally

    Then look for the final inertia:

    Final Inertia = 600 + (20 * (3^2)) = 780 kg m^2

    Now use conservation of angular momentum:

    (I final) (W final) = (I initial) (w initial) = 780w = 600 (0.80)

    w = (600*0.80) / 780

    So, final angular velocity:

    W = 0.6154 rad/s

    ~0.62 rad/s
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