A spring has a spring constant of 48 N/m. The end of the spring hangs 8 m above the ground.

How much weight can be placed on the spring so that the end of the spring is 2 m above the ground?

96 N

288 N

384 N

480 N

In order to determine the force needed in order for the end of the spring to be 2 m above the ground, we use Hooke's law which expressed as Force = k (x2-x1). We calculate as follows:

F = k (x2-x1)

F = 48 (8-2)

F = 288 N

Therefore, the correct answer is option 2.