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11 July, 01:03

When landing after a spectacular somersault, a 45.0 kg gymnast decelerates by pushing straight down on the mat. Calculate the force she must exert if her deceleration is 8.00 times the acceleration of gravity.?

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  1. 11 July, 02:39
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    So the force that the gymnast with a mass m=45 kg, has to exert against the ground to stop if her acceleration is a=8*g, where g=9.81 m/s², can be obtained from the Newtons second law: F=m*a, where F is the force, m is the mass and a is acceleration.

    F=m*a=m*8*g=45*8*9.81=3531.6 N.

    So the force that a gymnast has to exert on the mat in order to stop is F=3531.6 N.
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