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28 December, 01:20

An object is projected horizontally at 8.0 m/s from the top of a 122.5 m cliff. how far from the base of the cliff will the object strike the ground?

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  1. 28 December, 03:58
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    Refer to the diagram shown below.

    Assume g = 9.8 m/s² and neglect air resistance.

    All quantities are measured as positive upward.

    The vertical launch velocity is u = 0.

    Let t = the time of flight.

    Use the formula s = ut + (1/2) at²

    Then

    (-122.5 m) = 0 + (1/2) * (-9.8 m/s²) * (t s) ²

    t² = 122.5/4.9 = 25

    t = 5 s

    The horizontal distance traveled is

    d = (8.0 m/s) * (5 s) = 40 m

    Answer: 40 m
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