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30 August, 11:35

A 39.5 kg child stands at the center of a 125 kg playground merry-go-round which rotates at 3.10 rad/s. If the child moves to the edge of the merry-go-round, what is the new angular velocity of the system? Model the merry-go-round as a solid disk

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  1. 30 August, 15:24
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    Using the law of conservation of angular momentum, we have

    I1 w1 = I2 w2

    ie., m1r^2/2 x w1 = (m1r^2/2 + m2r^2) w2

    ie., new angular velocity w2 = m1 w1 / (m1 + 2m2) = 125 x 3.1 / (125 + 2 x39.5)

    = 1.8995 = 1.9 rad / sec (nearly)
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