Ask Question
31 December, 04:16

If the stone loses 10% of its speed in 10 s of grinding, what is the force with which the man presses the knife against the stone?

+1
Answers (1)
  1. 31 December, 06:35
    0
    W1=200rpm*2pi/60=20.9rad/s

    w2=200rpm-.10 (200rpm) = 180rpm

    180rpm*2pi/60=18.8rad/s

    a = (18.8-20.9) / 10 = -.21rad/s^2

    I=1/2 (28) (.15) ^2

    I=.315kg*m^2

    Torque = -.21 (.315) =.06615 N*m

    Friction force = -.06615/.15=-.441 N

    Normal force of man=.441/.2 = 2.205 N

    Final answer: - 2.205 N
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If the stone loses 10% of its speed in 10 s of grinding, what is the force with which the man presses the knife against the stone? ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers