Ask Question
12 September, 15:25

If a wood is drowned in water up to 2/3 of its volume and the same wood is dipped in a oil upto 9/10 of its volume. What's the density of wood and the relative oil?

Density of water - 1000kgm-3

+3
Answers (1)
  1. 12 September, 18:13
    0
    S. G. or specific gravity is the ratio of the density of an object to a fluid. It also is the fraction of the object's volume that would be submerged if the object were placed in the fluid. (note: if S. G.>1, the object will sink)

    S. G. = density (wood) / density (water)

    2/3 = density (wood) / 1000

    density (wood) = 2000/3 kg/m^3 = ~666.67 kg/m^3

    S. G. = density (wood) / density (oil)

    9/10 = 2000/3 / density (oil)

    density (oil) = 2000/3 / 9/10 = 20000/27 kg/m^3 = ~740.74 kg/m^3
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If a wood is drowned in water up to 2/3 of its volume and the same wood is dipped in a oil upto 9/10 of its volume. What's the density of ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers