A small ball of mass m is aligned above a larger ball of mass M = 0.63kg (with a slight separation) and the two are dropped simultaneously from a height of 1.8m. If the larger ball rebounds elastically from the floor and the small ball rebounds elastically from the larger ball what value of m results in the larger ball stopping when it collides with the small ball?

Question

Physics

Matthew

Yesterday, 09:30

A small ball of mass m is aligned above a larger ball of mass M = 0.63kg (with a slight separation) and the two are dropped simultaneously from a height of 1.8m. If the larger ball rebounds elastically from the floor and the small ball rebounds elastically from the larger ball what value of m results in the larger ball stopping when it collides with the small ball?

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Maci Ferguson · Answer 1

a) M is the big one

m is the little one

v is the speed of each of them when they impact

V = speed of mii after collision

Conservation of momentum

Mv - mv = mV

Conservation of energy

1/2Mv^2 + 1/2mv^2 = 1/2 mV^2

This pair simplify to give

M = 3m

V = 2v

So m = 0.21kg

and h = 4. 2.7 = 10.8 m Source (s) : Old teacher