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25 May, 05:45

A student increases the temperature of a 300 cm^3 balloon from 30c to 60c. what will the new volume of the ballon be

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  1. 25 May, 08:21
    0
    From Charles law the volume of a fixed mass of gas is directly proportional to the absolute temperature when pressure is kept constant.

    Volume α temperature, mathematically; k = V/T

    Therefore, comparing two gases V1/T1 = V2/T2

    V1 = 300 cm³ T1 = 30°C (30 + 273 = 303K) V2 = ? T2 = 60°C (60 + 273 = 333K)

    Thus, 300/303 = V2/333

    V2 = (300 * 333) / 303

    = 329.703 cm³

    Hence the new volume will be 329.703 cm³
  2. 25 May, 09:27
    0
    This problem uses the ideal gas law, PV = nRT. T for temperature must be in Kelvin, so we add 273.15 to the Celsius temperatures. We are then changing T from 303.15 K to 333.15K. The ratio of the temperatures 333.15/303.15 ~ = 1.1. So holding pressure constant, the new volume of the balloon will be approximately 10% larger, or 330cm^3.
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