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17 March, 02:56

A charged paint is spread in a very thin uniform layer over the surface of a plastic sphere of diameter 10.0cm, giving it a charge of - 15.0_C.

A: Find the electric field just inside the paint layer.

B: Find the electric field just outside the paint layer.

C: Find the electric field 6.00cm outside the surface of the paint layer.

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  1. 17 March, 06:52
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    (1/4πϵ0) q / r2 = (9∗ 109) ∗ (-15) / (0.06∗0.06) = 3.75∗ 101 3newton/coloum EdA = q enclosed ϵ0 EA = q enclosed ϵ0 E (4π r2) = q enclosed ϵ0 E = q enclosed (4π r2) ϵ0 E = - 15X 10 - 6 C (4π (5X 10 - 2+6X 10 - 2) 2) ϵ0 roadjester 3 years ago I converted the radius to meters You want the electric field 6cm outside of the sphere so the radius is 5 cm (half of the diameter of the sphere) plus the 6cm so the net radius is actually 11c
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