An 80 kg hockey player is skating at 5 m/s. He collides with the wall and comes to a stop in. 2 s. What was the force of his impact on the wall

Question

Physics

Freddy Rowe

9 June, 13:35

An 80 kg hockey player is skating at 5 m/s. He collides with the wall and comes to a stop in. 2 s. What was the force of his impact on the wall

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Answers (2)

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Mason Esparza · Answer 1

In this question, a hockey player with mass 80kg is skating with velocity 5m/s and then collide with a wall for 0.2 seconds. Force formula is mass multiplied by acceleration.

In this case, the velocity is changed into 5m/s into 0m/s in 0.2 second. Then the acceleration is: (5m/s - 0m/s) / 0.2 second = 25m/s^2

Then, the force on his impact should be:

force = mass*acceleration

force = 80kg * 25 m/s^2 = 2000N

Conrad Camacho · Answer 2

F = mass * acceleration

The 80kg hockey player was travelling at 5 m/s when he hit the wall. He stopped in. 2 s, which means that he decelerated by 5m/s in. 2 seconds.

This means this deceleration was 5 m / 0.2 s² = 25 m/s²

To calculate Force, multiply mass times acceleration

80kg times 25m/s² = 2,000 N