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30 May, 15:35

A helicopter is traveling at 86km/h at an angle of 35° to the ground. what is the value of Ax and Ay?

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  1. 30 May, 18:10
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    A component of an object moving at a certain velocity can be split into its x and y components (sometimes there is a z component too, but in the case of a question like this, we can imagine the plane the helicopter is travelling in to be 2 dimensions).

    Therefore, we can draw a triangle - the hypotenuse having length 86 and being 35 degrees from the ground.

    Since the angle ACB (assuming A to be bottom left and B to be top) is a right angle, we can now work with trigonometry:

    Sinx = opp/hyp and Cosx = adj/hyp which will give us the components of the vector. Substituting the known values into the equations and rearranging:

    86Sin (35) = Opp = 49.3km/h

    86Cos (35) = Adj = 70.4km/h

    Therefore, the horizontal component (Ax) is 70km/h and the vertical component (Ay) is 49km/h
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