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10 May, 07:41

The diagram shows a 15-kg box resting on a wedge which has an angle of inclination of 30° and a coefficient of friction of 0.15. Find the value of the vector Fg.

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  1. 10 May, 08:24
    0
    The correct answer is B. 147.15 N
  2. 10 May, 11:10
    0
    We calculate first for the normal force, Fn, which is equal to the product of the force and the cosine of the given angle,

    Fn = (15 kg) (9.8 m/s²) (cos 30°)

    Fn = 127.30 N

    Then, to calculate for the Fg, we multiply the normal force by the given coefficient.

    Fg = (127.30 N) (0.15) = 19 N

    The nearest value is letter A.
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Home » Physics » The diagram shows a 15-kg box resting on a wedge which has an angle of inclination of 30° and a coefficient of friction of 0.15. Find the value of the vector Fg.
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