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7 July, 03:55

Two lightbulbs each with a resistance of 20 Ω are connected in series to a voltage of 120 V. If a third lightbulb of 20 Ω is added to the circuit, how will the current change?

A. It will remain the same.

B. It will increase from 40 A to 60 A.

C. It will decrease from 30 A to 20 A.

D. It will decrease from 60 A to 20 A.

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Answers (1)
  1. 7 July, 07:09
    0
    Total resistance = 20 + 20=40Ω

    Voltage=120v

    Current = voltage/resistance = 30A

    After adding another bulb:

    Total resistance = 20 + 20 + 20 = 60Ω

    Voltage=120v

    Current=120/60 = 20A

    Answer is option C
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