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11 November, 07:38

A ball is dropped off of a tall building and falls for 2 seconds before landing on a balcony. a rock is then dropped from the top of the building and falls for 4 seconds before landing on the ground. how does the final speed (meaning the speed it had just before landing) of the rock compare to the final speed of the ball?

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  1. 11 November, 10:28
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    Using the formula Final speed = initial speed + gravity * time, we can compare the results.

    Being gravity approximately 9.8 m/s^2, and being both the rock and the ball dropped, we can assume that the initial speed of both is zero, so:

    Ball: 9.8m/s^2 * 2s = 18.6 m/s

    Rock: 9.8 m/s^2 * 4 = 37.2 m/s

    The speed of the rock is the double of the speed of the ball at the moment just before landing, because it has been dropped in a greater height than the ball, allowing the rock to reach a greater speed than the ball.
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