A cart moves along a track at a velocity of 3.5 cm/s. when a force is applied to the cart, its velocity increases to 8.2 cm/s. if it takes the cart 1.5 seconds to reach 8.2 cm/s, what is the acceleration of the cart? round your answer to the nearest tenth.

Question

Physics

Kyler Wong

8 November, 20:10

A cart moves along a track at a velocity of 3.5 cm/s. when a force is applied to the cart, its velocity increases to 8.2 cm/s. if it takes the cart 1.5 seconds to reach 8.2 cm/s, what is the acceleration of the cart? round your answer to the nearest tenth.

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Answers (1)

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Ellis Myers · Answer 1

Acceleration, in physics, is the rate of change of velocity of an object with respect to time. Anytime an object's velocity is changing, the object is said to be accelerating. It can be calculated as follows:

acceleration = 8.2 - 3.5 / 1.5 = 3.1 m/s ²

Hope this answers the question.