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31 August, 06:07

If an object is projected upward with an initial velocity of 127 ft per? sec, its height h after t seconds is h equals negative 16 t squared plus 127 th=?16t2+127t. find the height of the object after 55 seconds.

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  1. 31 August, 06:32
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    To determine the height of the object given the time, we simply use the given relation between height and time in the problem statement. It is given as:

    h = - 16t^2 + 127t

    We substitute 55 seconds to t and obtain,

    h = - 16 (55) ^2 + 127 (55)

    h = - 41415
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