Ask Question
Today, 17:16

What is the net force in the x-direction? 30 N 34 N 55 N 65 N

+2
Answers (1)
  1. Today, 18:04
    0
    Answer

    34 N

    Explanation.

    I think the question is not complete ... It should be "A box is pulled to the right with a force of 65 N at an angle of 58 degrees to the horizontal. The surface is frictionless. The free body diagram is shown. What is the net force in the x-direction? 30 N 34 N 55 N 65 N"

    We should find the horizontal component of the force 65 N.

    Since 65 N is at an angle of 58° to the horizontal, we are required to find the horizontal force.

    cosФ = adjacent/hypotenuse

    let x be the net required (the component of 65N)

    cos 58 = x/65

    x = 65 * cos 58

    = 34.44 N
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the net force in the x-direction? 30 N 34 N 55 N 65 N ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers