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14 November, 17:16

What is the net force in the x-direction? 30 N 34 N 55 N 65 N

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  1. 14 November, 18:04
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    Answer

    34 N

    Explanation.

    I think the question is not complete ... It should be "A box is pulled to the right with a force of 65 N at an angle of 58 degrees to the horizontal. The surface is frictionless. The free body diagram is shown. What is the net force in the x-direction? 30 N 34 N 55 N 65 N"

    We should find the horizontal component of the force 65 N.

    Since 65 N is at an angle of 58° to the horizontal, we are required to find the horizontal force.

    cosФ = adjacent/hypotenuse

    let x be the net required (the component of 65N)

    cos 58 = x/65

    x = 65 * cos 58

    = 34.44 N
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