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9 October, 05:39

At what distance along the central axis of a uniformly charged plastic disk of radius R = 0.525 m is the magnitude of the electric field equal to 1/5 times the magnitude of the field at the center of the surface of the disk?

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  1. 9 October, 07:26
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    The general formula for the strength of magnetic field is written below:

    E = kQ/d²,

    where k is the Coulomb's constant

    Q is the charge of the object

    d is the distance

    The ratio of the magnetic fields should be 1/5:

    E₁/E₂ = 1/5

    kQ/d₁² : kQ/d₂² = 1/5

    The k and Q will be cancelled out because only the distance is varied, the charge does not change. The equation becomes

    1/d₁² : 1/d₂² = 1/5

    Substitute d₁ = 0.525 m

    1 / (0.525 m) ² : 1/d₂² = 1/5

    Solving for d₂,

    d₂ = 0.235 m

    The distance is 0.235 m along the central axis.
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