The acceleration due to the earth's gravity, in si units, is 9.8 m/s2. in the absence of air friction, a ball is dropped from rest. its speed on striking the ground is exactly 60 m/s. for what time interval was the ball falling?

Question

Physics

Jacob Keith

22 September, 08:12

The acceleration due to the earth's gravity, in si units, is 9.8 m/s2. in the absence of air friction, a ball is dropped from rest. its speed on striking the ground is exactly 60 m/s. for what time interval was the ball falling?

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Answers (1)

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Darnell · Answer 1

We don't know anything about the amount of distance it travels, but that's okay. The only equation we need here is

velocity (final) = velocity (initial) + acceleration * time

vf = vi + (a * t)

The ball is dropped from rest, so vi = 0 m/s.

We want it so that the ball hits the ground with a final velocity of 60 m/s, so vf = 60 m/s.

We are given the acceleration due to gravity, a = 9.8 m/s^2.

We are solving for the time, t = ?.

Now we just plug in the values.

vf = vi + (a * t)

60 m/s = 0 m/s + (9.8 m/s^2) * (t)

60 = 9.8t

60 / 9.8 = t

t = 6.122 s

Hopefully this is the right answer.