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21 December, 06:46

Two hockey players are traveling at velocities of v1 = 14 m/s and v2 = - 16 m/s when they undergo a head-on collision. After the collision, they grab each other and slide away together with a velocity of - 3.9 m/s. Hockey player 1 has a mass of 115 kg. What is the mass of the other player?

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  1. 21 December, 10:43
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    Conservation of momentum says:

    m1u1 + m2u2 = m1v1+m2v2

    115 (14) + m2 (-16) = (115+m2) (-3.9)

    129 - 16m2 = - 448.9 - 3.9m2

    577.5 = 12.1m2

    47.7272 ... b = m2

    m2 = 47.2 (this seems a little strange, so you might have to check my maths, but the process should be correct)
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