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28 October, 20:54

Zoe has 25 grams of water (c = 4.186) at 10°C, which she mixes with 12 grams of water at 30°C. Assume that no heat is lost to the surroundings. What is the final temperature of the two liquids? The answer is expressed to the nearest whole number.

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Answers (2)
  1. 28 October, 22:47
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    Since heat here is conserved that means that the heat out is equal to the heat in. We use the expression Q = mC (T2-T1). We caclulate as follows:

    Q absorbed = Q released

    m1 C (T-T1) = - m2 C (T-T1)

    C can be cancelled since they are the same substance.

    m1 (T-T1) = - m2 (T-T1)

    25 (T-10) = - 12 (T-30)

    T = 16.49 degrees Celsius
  2. 29 October, 00:53
    +1
    T = 16.49 degrees Celsius
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