A toy car goes over a small ramp at a horizontal velocity of 1.21 m/s and decelerates at 0.131 m/s2 while in the air. The total time elapsed was 0.342 seconds. What was the horizontal distance traveled?

We need to considerate only the horizontal component of the motion of the toy car.

The formula for the distance in a decelerated motion is:

s = s₀ + v₀·t - 1/2·a·t²

where:

s₀ = initial position = 0

v₀ = initial velocity = 1.21 m/s

t = time elapsed = 0.342 s

a = deceleration = 0.131 m/s²

Plugging in numbers:

s = 0 + 1.21*0.342 - 0.5*0.141 * (0.342) ²

= 0.406 m

Hence, the toy car traveled a distance of about 41 cm.