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20 April, 19:29

A 33.0 g iron rod, initially at 22.7 ∘c, is submerged into an unknown mass of water at 63.3 ∘c, in an insulated container. the final temperature of the mixture upon reaching thermal equilibrium is 58.5 ∘c. part a what is the mass of the water? express your answer to two significant figures and include the appropriate units.

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  1. 20 April, 20:25
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    The specific heat capacity of iron = 0.450 J/g°C

    and the specific heat water = 4.18 J/g°C

    Heat gained by iron;

    = 33 * 0.450 (58.5-22.7)

    = 531.63 J

    Heat lost by water; assuming the mass of water m

    = m * 4.18 * (63.3 - 58.5)

    = 20.064m

    But; heat gained = heat lost

    20.064 m = 531.63

    m = 26.497 g

    Therefore, the mass of water is 26.497 g
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