Using the conversion factor from eV (electron volts) to joules, determine which energy line for an electron dropping from one energy level to another would show a line at 435 nm in an emission spectrum. Use the formulas and the energy level information below to answer the question.

Needed constants:

1.00eV = 1.6 * 10^-19 J

c = 3.00 * 10^8 m/s

h = 6.63 * 10^-34 J*s

Energy Level Values:

E6: E = - 0.378 eV

E5: E = - 0.544 eV

E4: E = - 0.850 eV

E3: E = - 1.51 eV

E2: E = - 3.403V

Question

Physics

Emery Sosa

19 December, 14:25

Using the conversion factor from eV (electron volts) to joules, determine which energy line for an electron dropping from one energy level to another would show a line at 435 nm in an emission spectrum. Use the formulas and the energy level information below to answer the question.

Needed constants:

1.00eV = 1.6 * 10^-19 J

c = 3.00 * 10^8 m/s

h = 6.63 * 10^-34 J*s

Energy Level Values:

E6: E = - 0.378 eV

E5: E = - 0.544 eV

E4: E = - 0.850 eV

E3: E = - 1.51 eV

E2: E = - 3.403V

+2

Answers (1)

Know the Answer?

Pumpkin · Answer 1

The formula used to solve this is:

E = hc/λ

The given values can then be subsituted into the equation to sovle for the energy:

E = (6.63 x 10^-34 J-s) (3 x 10^8 m/s) / 435 x10^-9 m

E = 4.5724 x 10^-19 J

converting to electron volts

E = 4.5724 x 10^-19 J * 1.00eV / 1.6 * 10^-19 J

E = 2.86 eV

The closest energy line is

E2