A radioactive sample has a count rate of 800 counts per minute. One hour later, the count rate has fallen to 100 counts per minute. What is the half-life of the sample?

Radioactivity equation states:

N = No e^ (-0.693t/t1/2) - - - Where t = time, t1/2 = half-life, N = count after time t, No = Initial count

Using the values given;

100 = 800 e^ (-0.693*1/t1/2)

100/800 = e^ (-0.693t/t1/2)

0.125 = e^ (-0.693/t1/2)

Taking natural logs on both sides;

log 0.125 = - 0.693/t1/2 * log (e)

-0.9031 = - 0.693/t1/2 * 0.4323

t1/2 = (-0.693*0.4323) / (-0.9031) = 0.3317 hours

Therefore, half-life of the sample is approximately 0.3317 hours