It is friction that provides the force for a car to accelerate, so for high-performance cars the factor that limits acceleration isn't the engine; it's the tires. you may want to review (pages 138 - 142). part a for typical rubber-on-concrete friction, what is the shortest time in which a car could accelerate from 0 to 60 mph? suppose that μs=1.00 and μk=0.80.

Question

Physics

Frankie Bailey

9 February, 05:35

It is friction that provides the force for a car to accelerate, so for high-performance cars the factor that limits acceleration isn't the engine; it's the tires. you may want to review (pages 138 - 142). part a for typical rubber-on-concrete friction, what is the shortest time in which a car could accelerate from 0 to 60 mph? suppose that μs=1.00 and μk=0.80.

+4

Answers (1)

Know the Answer?

Alvaro Strong · Answer 1

Let the acceleration of the system is a and the time to reach 60 mph is t, so

ax = (μs - μr) * g

ax = (1.00-0.80) (9.8 m/s2) = 1.96 m/s2

Then I used acceleration in this equation:

vf = vi + ax * t

60 mph = 0 mph + (1.96 m/s2) t

t = (60 mph/1.96 m/s2) (0.447 m/s / 1 mph)

t = 13.68 s