A 0.500 kg object is thrown vertically upward with an average applied force of 8.20 N by a student. The force is applied through a displacement of 1.50 m

a. What is the average net force acting on the object?

b. What is the velocity of the object when it leaves the student's hand? (Assume initial velocity is zero)

Question

Physics

Guerra

26 April, 10:22

A 0.500 kg object is thrown vertically upward with an average applied force of 8.20 N by a student. The force is applied through a displacement of 1.50 m

a. What is the average net force acting on the object?

b. What is the velocity of the object when it leaves the student's hand? (Assume initial velocity is zero)

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Answers (1)

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Jazmyn Newton · Answer 1

Average net force:

∑F = Fapp + Fgrav = 8.20 + (-9.81m/s²) (0.500 kg)

= 3.295 N

= 3.30 N

Velocity of object

∑F = ma

a = ∑F / m = 3.295 N / 0.500 kg = 6.59 m/s²

v² = v₀² + 2ad

v = √ (v₀² + 2ad)

v = √[ 0² + 2 (6.59m/s²) (1.50m) ]

v = 4.45 m/s